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Rosy aged 21 years married to Ramesh aged 26 years. After 3 years of their marriage, they are blessed with a baby girl. Find the sum of their ages after the birth of their child.
After 3 years, Rosy’s age = 21 + 3 = 24 years Ramesh’s age = 26 + 3 = 29 years Therefore, sum of their ages after the birth of their child = 24 + 29 = 53 years
The present age of a father is 20 years less than three times his son’s present age. If the present age of the son, in years is an integer, which of the following choices represent the present age of the father?
Let the present ages of the father and the son be f and s respectively. f = 3s − 20 ⇒ s = (f + 20)/3 As s is an integer, so (f + 20) is divisible by 3. Going by the choices it must be 55 years.
There are three members in a family – husband, wife and their son. Husband’s age is thrice his son’s age and wife is three years younger than his husband. What is the respective ratio of ages of son, husband and wife if their average age is 41?
Let son’s age = x Husband’s age = 3x Wife’s age = 3x – 3 According to question- ⇒ x + 3x + (3x – 3) = 41 × 3 ⇒ 7x = 126 ⇒ x = 18 Son’s age = 18 years Husband’s age = 18 × 3 = 54 years Wife’s age = 18 × 3 – 3 = 51 years Required ratio = 18 : 54 : 51 = 6 : 18 : 17
Udit is 8 years older than his brother. His brother is 24 years younger than their mother. If the ratio between the ages of Udit and their mother is 7 : 11. What will be the age of Udit’s brother after 3 years?
Let the age of Udit’s brother be ‘a’. Udit’s age = a + 8 Mother’s age = a + 24 Thus, (a+8)/(a+24) = 7/11 ⇒ 11a + 88 = 7a + 168 ⇒ 4a = 80 ⇒ a = 20 years Thus, brother’s age 3 years later = 23 years
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The ages of Nishi and Vinnee are in the ratio of 6: 5 respectively. After 9 yr the ratio of their ages will be 9: 8. What is the difference in their ages?
Suppose the ages of Nishi and Vinnee are 6x and 5x yr. (6x+9)/(5x+9) = 9/8 ⇒ 48x + 72 = 45x + 81 ⇒ 48x – 45x = 81 – 72 ⇒ 3x = 9 ⇒ x = 3 Required difference, 6x – 5x = x = 3 years
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